0,7x^2-3,5x=0

Solution for 0,7x^2-3,5x=0 equation:

0.7x^2-3.5x=0

a = 0.7; b = -3.5; c = 0;
Δ = b2-4ac
Δ = -3.52-4·0.7·0
Δ = 12.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.5)-\sqrt{12.25}}{2*0.7}=\frac{3.5-\sqrt{12.25}}{1.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.5)+\sqrt{12.25}}{2*0.7}=\frac{3.5+\sqrt{12.25}}{1.4}
$